Question
Find the value of the following, using suitable properties:
a) 406×516
b) 8 ×291×125
[3 MARKS]
Answer: Option A
:
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Steps: 1×2=2 Marks
Answer: 0.5×2=1 Mark
a) By distributive law
406×516 = (400 + 6)×(500 + 16)
= 200000 + 96 + 6400 + 3000 = 2,09,496
b) By distributive law
8 ×291×125=(4×2)×(290+1)×(25× 5)=(25× 4)×(5×2)×(290+1)
= 100 × 10 × (290+1) = 1000 × (290+1)
= 290000 + 1000 = 291000
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