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Question
Decarbonylation reaction of [cis-(CH3CO)Mn(13CO)(CO)4] yields X,Y and Z, whereX =[(CH3)Mn(CO)5]; Y = [cis-(CH3)Mn(13CO)(CO)4]; Z = [trans-(CH3)Mn(13CO)(CO)4]The molar ratio ofthe products(X : Y : Z) in this reaction is
Options:
A .  1 : 1 : 1
B .  1 : 2 : 1
C .  1 : 1 : 2
D .  2 : 1 : 1
Answer: Option B


-NA-



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