Answer: Option D
:
D
Brandon experienced a free fall from the top of the tower and, thus, was under the acceleration due to gravity (g).
Distance travelled in 2 seconds is equal to the height of tower which can be found out by applying equation of motion.
From second equation of motion, we have,
$s=u\times t+\frac{1}{2}\times g{t}^2$
where s- height of tower, u- initial velocity, t-time taken and g- acceleration due to gravity.
Since he fell from rest, u = 0
$s=\frac{1}{2}\times g{t}^2=\frac{1}{2}\times 10\times 2^2=20m$
Therefore, height of tower is 20 m.