Question
What is the buoyant force experienced by a cube of side 10 cm which is completely immersed in water?
(Take g=10 m s−2 and density of water =1000 kg m−3)
(Take g=10 m s−2 and density of water =1000 kg m−3)
Answer: Option B
:
B
Given,
Length of each side of the cube, l=10cm=0.1m
Density of water, ρ=1000kgm−3
Acceleration due to gravity, g=10ms−2
Volume of the cube, V=l3=(0.1)3=0.001m3
Archimedes' principle states that the buoyant force acting on an object is equal to the weight of the fluid displaced by it.
In the given case, volume of cube is equal to the volume of water displaced.
Mass of waterdisplaced (m) = Density of water × Volume of water displaced
⇒m=1000kgm−3×0.001m3
=1kg
Weight of water displaced, W =mg
⇒W=1×10 =10N
Hence, the buoyant force is 10N.
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:
B
Given,
Length of each side of the cube, l=10cm=0.1m
Density of water, ρ=1000kgm−3
Acceleration due to gravity, g=10ms−2
Volume of the cube, V=l3=(0.1)3=0.001m3
Archimedes' principle states that the buoyant force acting on an object is equal to the weight of the fluid displaced by it.
In the given case, volume of cube is equal to the volume of water displaced.
Mass of waterdisplaced (m) = Density of water × Volume of water displaced
⇒m=1000kgm−3×0.001m3
=1kg
Weight of water displaced, W =mg
⇒W=1×10 =10N
Hence, the buoyant force is 10N.
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