Question
An amplitude modulated wave is modulated to 50%. What is the saving in power if carrier as well as one of the side bands are suppressed
Answer: Option C
:
C
Psb = Pc(ma2)2= Pc(0.52)4=0.0625Pc
Also P = Pc(1+ma22)=Pc(1+(0.5)22)=1.125Pc
∴ % saving = (1.125Pc−0.0625Pc)1.125Pc×100 = 94.4%
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:
C
Psb = Pc(ma2)2= Pc(0.52)4=0.0625Pc
Also P = Pc(1+ma22)=Pc(1+(0.5)22)=1.125Pc
∴ % saving = (1.125Pc−0.0625Pc)1.125Pc×100 = 94.4%
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