A particle is undergoing SHM along a straight line so that its period is 12 s. T

Question

A particle is undergoing SHM along a straight line so that its period is 12 s. The time it takes in traversing a distance equal to half its amplitude from the equilibrium position is

Options:

A . 3 s

B . 2 s

C . 1 s

D . 0.5s

Answer: Option C
:
C

y = A s i n ω t

\frac{A}{2} = A s i n \frac{2 π}{12} t; \frac{1}{2} = s i n \frac{π}{6} t ∴ \frac{π t}{6} = \frac{π}{6} \Rightarrow t = 1 s

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