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Question


a3 - b3 is always divisible by:


Options:
A .   a - b
B .   a × b
C .   a + b
D .   2a + b 
Answer: Option A
:
A

Take a=2 and b=1 and check.
Alternatively, we know the algebraic identity,


a3b3=(ab)(a2+2ab+b2)


 Hence , we can see that (ab) is a factor of a3 - b3
Thus, a3 - b3 is divisible by (ab)



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