A train met with an accident 80 km away from old Delhi railway station. It travels at 56th of the usual speed and reaches the Kanpur central 1 hour 12 min late. Had the accident taken place 120 km further. It would have been only 1 hour late. What is the distance between Old Delhi Railway station and Kanpur Central?
:
B
Since the speed is decreased by 1/6. So, the time will be increased by 15, which is equal to 1 hour 12 minutes. It means the normal time required for this remaining part of journey is 5 × 72 min = 360 min = 6 hour
Now, accident is supposed to happen 120 km further.
Since, the speed is decreased by 16. So, the time will be increased by 15, which is equal to 1 hour. Hence normal time required for this remaining part of journey is 5 × 1 = 5 hour.
Thus , it is clear that when the trains runs 120 km of its normal speed it takes 1 hour less, which implies that in 1 hour the train can run 120km with its normal speed. Thus the normal speed of train is 120km/h.
Since the train requires 6 hours at its normal speed of 120 km/h for the rest part of journey. So,
AK = 120 × 6 = 720.
Thus,
The total distance = Distance travelled before accident + Distance travelled after accident
= 80 + 720 = 800.
Option (a).
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