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A steel ball (density ρsteel = 7200 kg/m3) is placed in an upward moving liquid Al (density ρAl = 2360 kg/m3, viscosity μAl = 1 * 10“3 Pa.s and Reynolds number = 5 * 105). The force (F) exerted on the steel ball is expressed as F = f Ï€ R2(ρAl v2/2)where, f is friction factor (=0.2), v is the velocity of liquid Al and R is the radius of steel ball.The terminal velocity of a fine spherical steel particle having diameter dp, in μm range, if allowed
to fall in a quiescent liquid Al bath, is
Options:
A .  5.2 * 106 dp2
B .  2.6 * 106 dp2
C .  1.3 * 106 dp2
D .  6.6 * 105 dp2
Answer: Option B


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