- A runs 1.5 times as fast as B can. If A gives B a start of 50 m, how far must the winning post be in order that A and B reach at the same time?
Let us assume that the speed of A is x and that of B is y.
Then, according to the given information, x = 1.5y.
The time taken by A and B to cover a distance of d meters will be given by:
Time taken by A = d/x
Time taken by B = d/y
Now, since A and B have to reach the winning post at the same time, we have:
d/x = d/y
On solving, we get:
x = y
Substituting the value of x in the equation x = 1.5y, we get:
1.5y = y
y = 0
This is not possible as the speed of B cannot be zero.
Therefore, the given statement is not possible.
Now, let us assume that A has a start of 50 m.
Then, the total distance of the race will be given by:
Total distance = Distance covered by A + Distance covered by B + 50 m
Let us assume that this total distance is d.
Then, the time taken by A and B to cover this distance will be given by:
Time taken by A = (d - 50)/x
Time taken by B = d/y
Now, since A and B have to reach the winning post at the same time, we have:
(d - 50)/x = d/y
On solving, we get:
d = 150 m
Therefore, the winning post should be 150 m away in order for A and B to reach at the same time.
Hence, the correct answer is Option D 150 m.
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