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Question
A plane wall of thickness δ has its surfaces maintained at temperatures T₁ and T₂. The wall is made of a material whose thermal conductivity varies with temperature according to the relation k = k₀ T². Find the expression to work out the steady state heat conduction through the wall?
Options:
A .  Q = 2A k₀ (T₁³ – T₂³)/3 δ
B .  Q = A k₀ (T₁³ – T₂³)/3 δ
C .  Q = A k₀ (T₁² – T₂²)/3 δ
D .  Q = A k₀ (T₁ – T₂)/3 δ
Answer: Option B
Answer: (b).Q = A k₀ (T₁³ – T₂³)/3 δ

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