With variable thermal conductivity, Fourier law of heat conduction through a pla

Question

With variable thermal conductivity, Fourier law of heat conduction through a plane wall can be expressed as

Options:

A . Q = -k0 (1 + β t) A d t/d x

B . Q = k0 (1 + β t) A d t/d x

C . Q = – (1 + β t) A d t/d x

D . Q = (1 + β t) A d t/d x

Answer: Option A
Answer: (a).Q = -k0 (1 + β t) A d t/d x

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