The mean thermal conductivity evaluated at the arithmetic mean temperature is represented by Options: A . &nbspkm = k0 [1 + β (t1 – t2)/2]. B . &nbspkm = k0 [1 + (t1 + t2)/2]. C . &nbspkm = k0 [1 + β (t1 + t2)/3]. D . &nbspkm = k0 [1 + β (t1 + t2)/2].

The mean thermal conductivity evaluated at the arithmetic mean temperature is re

Question

The mean thermal conductivity evaluated at the arithmetic mean temperature is represented by

Options:

A . km = k0 [1 + β (t1 – t2)/2].

B . km = k0 [1 + (t1 + t2)/2].

C . km = k0 [1 + β (t1 + t2)/3].

D . km = k0 [1 + β (t1 + t2)/2].

Answer: Option D
Answer: (d).km = k0 [1 + β (t1 + t2)/2].

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