Question
A person walking at 5/6th of his usual speed is 40 minutes late to his office. What is his usual travel time to his office?
Answer: Option A
LET HIS USUAL SPEED BE X KMPH, THE DISTANCE TO HIS OFFICE BE Y KM AND HIS USUAL TRAVEL TIME BE T HRS. Y = XT = (5/6)X * (T+(40/60)) SOLVING THE EQUATION,
T = 3.33 HRS = 3 HRS 20 MINUTES
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LET HIS USUAL SPEED BE X KMPH, THE DISTANCE TO HIS OFFICE BE Y KM AND HIS USUAL TRAVEL TIME BE T HRS. Y = XT = (5/6)X * (T+(40/60)) SOLVING THE EQUATION,
T = 3.33 HRS = 3 HRS 20 MINUTES
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