Question
A particle of mass M at rest decays into two particles of masses m1 and m2, having non-zero velocities. The ratio of the de-Broglie wavelengths of the particles, λ1λ2 is
Answer: Option C
:
C
By law of conservation of momentum
0=m1→v1+m2→v2⇒m1→v1=−m2→v2
- ve sign indicates that both he particles are moving in opposite direction. Now de-Broglie wavelengths
λ1=hm1v1 and λ2=hm2v2 ; ∴λ1λ2=m2v2m1v1=1
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:
C
By law of conservation of momentum
0=m1→v1+m2→v2⇒m1→v1=−m2→v2
- ve sign indicates that both he particles are moving in opposite direction. Now de-Broglie wavelengths
λ1=hm1v1 and λ2=hm2v2 ; ∴λ1λ2=m2v2m1v1=1
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