Question
A particle moves 3 m north, then 4 m east and finally 6 m south. What is the distance travelled and the displacement of the particle?
Answer: Option A
:
A and D
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A and D
Let the particle start from A and finally reach B as shown. Distance is the length of the actual path taken by it.
In this case,
distance = 3 m + 4 m + 6 m = 13 m
Displacement is the shortest distance between the initial and final position.
Here, displacement = AB
Using Pythagoras theorem,
AB =√(BC2+AC2)
=√(32+42) m=5 m.
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