Question
An express train going towards Delhi is travelling at a speed of 90 kmph. Brakes are applied so as to produce a uniform acceleration of –0.5m s−2 . Find how far the train will go before it is brought to rest.
Answer: Option C
:
C
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C
Given,
initial velocity, u=90 kmph = 90×518 =25 ms−1
acceleration, a= –0.5 ms−2
final velocity, v=0 (brakes are applied)
Let 's' be the distance travelled.
From the third equation of motion,
v2=u2+2as
0=252+(2×−0.5×s)
⇒ s=625 m
Hence the distance covered is 625 m.
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