Question
A man with $3/5$ of his usual speed reaches the destination 2$1/2$ hours late. Find his usual time to reach the destination.
Answer: Option B
Answer: (b)$3/5$ of usual speed will take $5/3$ of usual time.[Since, time & speed are inversely proportional]$5/3$ of usual time = usual time + $5/2$$2/3$ of usual time = $5/2$usual time = $5/2 × 3/2$= $15/4 = 3{3}/4$ hours. Using Rule 8,If an object travels certain distance with the speed of $A/B$ of its original speed and reaches its destination 't' hours before or after, then the taken time by object travelling at original speed isTime = $\text"A"/\text"(Difference of A and B)"$ × time (in hour)
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Answer: (b)$3/5$ of usual speed will take $5/3$ of usual time.[Since, time & speed are inversely proportional]$5/3$ of usual time = usual time + $5/2$$2/3$ of usual time = $5/2$usual time = $5/2 × 3/2$= $15/4 = 3{3}/4$ hours. Using Rule 8,If an object travels certain distance with the speed of $A/B$ of its original speed and reaches its destination 't' hours before or after, then the taken time by object travelling at original speed isTime = $\text"A"/\text"(Difference of A and B)"$ × time (in hour)
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