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Question
A function y(t) satisfies the differential equation d2y/dt2 -2 dy/dt + y = 0 and is subject to the initial conditions y(t = 0) = 0 and dy/dt (t = 0) = 1. The value of y(t = 1) is
Options:
A .  e
B .  0
C .  1
D .  -1
Answer: Option A


-NA-



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