Question
A father is twice as old as his son. 20 years ago, the age of the father was 12 times the age of the son. The present age of the father (in years) is:
Answer: Option E
- Let son's age = x. Then father's age = 2x
12 (x - 20) = (2x - 20) 10x = 220 x = 22
Father's present age = 44 years
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- Let son's age = x. Then father's age = 2x
12 (x - 20) = (2x - 20) 10x = 220 x = 22
Father's present age = 44 years
Was this answer helpful ?
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