Question
A car of 400 kg is moving on a circle path of radius 30 m with a speed of 40 km/h . When the driver applies he braes and the car continues to move along the circular path , what is the maximum deceleration possible if the tyres are limited to a total horizontal friction of 10.6 kN ?
Answer: Option B
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The net acceleration to car is provided by force of friction .
`:.` `a = sqrt(a_n^2 + a_t^2)`
`:.` `F = ma = m sqrt((v^2/r)^2 + a_t^2)`
or ` 10.6 xx 10^3 = m sqrt( v^4/r^2 + a_t^2)`
After solving , `a_t `= 6.36 m / `s^2`
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