Question
A cyclist is travelling on a circular section of highway of radius 2500 ft at the speed of 60 mile / h. The cyclist suddenly applies the brakes causing the bicycle to slow down at constant rate . Knowing that after eight second , the speed has been reduced to 45 mile /h . The acceleration of the bicycle immediately after the brakes have been applied is :
Answer: Option B
Was this answer helpful ?
Tangential acceleration ` a_1` = `(v_f - v_i)/(t)`
=` ((45 - 60)/(8)) (22/15)` ft/s
= `- 11/4` ft /`s^2`
The radial acceleration is `a_n` = ` v^2/r`
= `( (60 xx 22/15)^2)/(2500)` = 3.1 ft/`s^2`
`:.` `a = sqrt(a_n^2 + a_t^2)` = 4.14 ft / `s^2`
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution