A bucket is in the form of a frustum of a cone, its depth is 15 cm and the diame

Question

A bucket is in the form of a frustum of a cone, its depth is 15 cm and the diameters of the top and the bottom are 56 cm and 42 cm respectively. How many litres of water can the bucket hold ? (Take

π

\frac{22}{7}

)
__

Answer:
:

A Bucket Is In The Form Of A Frustum Of A Cone, Its Depth Is...

R = 28 cm
r = 21 cm
h = 15 cm
Capacity of the bucket =

\frac{1}{3} π h (R^{2} + r^{2} + R r)

\frac{1}{3} \times \frac{22}{7} \times 15 \times [(28)^{2} + (21)^{2} + (28) (21)] c m^{3}

\frac{22}{7} \times 5 \times [784 + 441 + 588] c m^{3}

\frac{22}{7} \times 5 \times 1813 c m^{3}

= 22× 5× 259

c m^{3}

= 28490

c m^{3}

\frac{28490}{1000}

liters
= 28.49 liters

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