A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km al

Question

A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?

Options:

A . 40 minutes

B . 1 hour

C . 1 hr 15 min

D . 1 hr 30 min

Answer: Option C

Rate downstream = \(\left(\frac{1}{10}\times60\right)\) km/hr = 6 km/hr

Rate upstream = 2 km/hr.

Speed in still water = \(\frac{1}{2}\) (6 + 2) km/hr = 4 km/hr.

So, Required time = \(\left(\frac{4}{5}\right)\) hrs = \(1\frac{1}{4} hrs\) = 1hr15min

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