A man can row three-quarters of a kilometre against the stream in 11 \(\fra

Question

A man can row three-quarters of a kilometre against the stream in 11 \(\frac{1}{4}\) minutes and down the stream in 7 \(\frac{1}{2}\) minutes. The speed (in km/hr) of the man in still water is:

Options:

A . 2

B . 3

C . 4

D . 5

Answer: Option D

We can write three-quarters of a kilometre as 750 metres,

and 11 \(\frac{1}{4}\) minutes as 675 seconds.

Rate upstream = \(\left(\frac{750}{675}\right)m/sec = \frac{10}{9}m/sec.\)

Rate downstream = \(\left(\frac{750}{450}\right)m/sec = \frac{3}{5}m/sec.\)

So, Rate in still water = \(\frac{1}{2}\left(\frac{10}{9}+\frac{3}{5}\right)m/sec\)

= \(\frac{25}{18}m/sec.\)

= \(\left(\frac{25}{18}\times\frac{18}{5}\right)km/hr\)

= 5 km/hr.

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