Question
A man rows to a place 48 km distant and come back in 14 hours. He finds that he can row 4 km with the stream in the same time as 3 km against the stream. The rate of the stream is:
Answer: Option A
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Suppose he move 4 km downstream in x hours. Then,
Speed downstream = \(\left(\frac{4}{x}\right)\) km/hr
Speed upstream = \(\left(\frac{3}{x}\right)\) km/hr
So, \(\frac{48}{(\frac{4}{x})} + \frac{48}{(\frac{3}{x})}= 14 or x=\frac{1}{2}\)
So, Speed downstream = 8 km/hr, Speed upstream = 6 km/hr.
Rate of the stream = \(\frac{1}{2}\) (8 - 6) km/hr = 1 km/hr
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