Question
A boat takes half time in moving a certain distance downstream than upstream. What is the ratio between the rate in still water and rate of current?
Answer: Option B
LET THE SPEED OF THE BOAT IN STILL WATER BE 4 KM/HR AND SPEED OF THE CURRENT BE U KM/HR.
RATE DOWNSTREAM = (U + V) KM/HR.
RATE UPSTREAM = (U- V)KM/HR
LET THE DISTANCE COVERED IN EACH CASE BE X KM.
THEN 2X/(U + V) = X / (U – V)
=> 2 (U – V) = ( U + V)
=> U =3V
=> U/V =3/1
Was this answer helpful ?
LET THE SPEED OF THE BOAT IN STILL WATER BE 4 KM/HR AND SPEED OF THE CURRENT BE U KM/HR.
RATE DOWNSTREAM = (U + V) KM/HR.
RATE UPSTREAM = (U- V)KM/HR
LET THE DISTANCE COVERED IN EACH CASE BE X KM.
THEN 2X/(U + V) = X / (U – V)
=> 2 (U – V) = ( U + V)
=> U =3V
=> U/V =3/1
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution