A bag has 6 red balls and 8 green balls. A ball is drawn from a bag without look

Question

A bag has 6 red balls and 8 green balls. A ball is drawn from a bag without looking into the bag. What is the probability of getting a green ball?

Options:

A . 34

B . 114

C . 37

D . 47

Answer: Option D
:
D

Probability = \frac{Number of favourable outcomes}{Total Number of outcomes}

Number of green balls (favourable outcomes) =8
Total number of balls (total outcomes) = 14
So probability of getting a green ball

= \frac{Number of green balls}{Total number of balls}

= \frac{8}{14}

= \frac{4}{7}

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