Question
6 boys and 3 girls are randomly placed in a row. Determine the probability of no two girls being placed adjacently.
Answer: Option B
:
B
The number of ways that no two girls are placed together is the number of ways in which 3 places marked with G are selected out of the SEVEN places.
___B___B___B___B____B____B____
This can be done in 7C3 ways.
Total no. of ways in which balls can be arranged = 10!(7!×3!) = 10C3. So, required probability = 7C310C3 = 724.
Hence option(b)
Was this answer helpful ?
:
B
The number of ways that no two girls are placed together is the number of ways in which 3 places marked with G are selected out of the SEVEN places.
___B___B___B___B____B____B____
This can be done in 7C3 ways.
Total no. of ways in which balls can be arranged = 10!(7!×3!) = 10C3. So, required probability = 7C310C3 = 724.
Hence option(b)
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution