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27 spherical iron balls of radius 5 cm each are melted and recasted into a big sphere.The radius of the big sphere is _____.


Options:
A .   3 cm
B .   9 cm 
C .   15 cm 
D .   5 cm 
Answer: Option C
:
C

Volume of the big iron ball will be equal to the volume of  27 small iron balls.
Let the radius of the big sphere be R cm.
Let the radius of the small sphere be
r cm = 5 cm.


 43×πR3=27×(43×πr3)
R3=27r3


R=3r=3×5=15 cm.



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