Question
27 spherical iron balls of radius 5 cm each are melted and recasted into a big sphere.The radius of the big sphere is _____.
Answer: Option C
:
C
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C
Volume of the big iron ball will be equal to the volume of 27 small iron balls.
Let the radius of the big sphere be R cm.
Let the radius of the small sphere be
r cm = 5 cm.
⇒ 43×πR3=27×(43×πr3)
⇒R3=27r3
R=3r=3×5=15 cm.
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