Question
14[√3cos23∘−sin23∘] =
Answer: Option D
:
D
14√3cos23∘−sin23∘
=12cos30∘cos23∘−sin30∘sin23∘
=12 cos(30∘+23∘) =12 cos53∘.
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:
D
14√3cos23∘−sin23∘
=12cos30∘cos23∘−sin30∘sin23∘
=12 cos(30∘+23∘) =12 cos53∘.
Was this answer helpful ?
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