s i n 2 A 1 + c o s 2 A . c o s A 1 + c o s A = Options: A . &nbsptan A2 B . &nbspcot A2 C . &nbspsec A2 D . &nbspcosec A2

Answer: Option A : A ( s i n 2 A 1 + c o s 2 A ) ( c o s A 1 + c o s A ) = 2 s i n A c o s A 2 c o s 2 A c o s A 1 + c o s A = s i n A 1 + c o s A = tan A 2

sin2A1+cos2A . cosA1+cosA =

Question

\frac{s i n 2 A}{1 + c o s 2 A}

\frac{c o s A}{1 + c o s A}

Options:

A . tan A2

B . cot A2

C . sec A2

D . cosec A2

Answer: Option A
:
A

(\frac{s i n 2 A}{1 + c o s 2 A})

(\frac{c o s A}{1 + c o s A})

\frac{2 s i n A c o s A}{2 c o s^{2} A}

\frac{c o s A}{1 + c o s A}

\frac{s i n A}{1 + c o s A}

= tan

\frac{A}{2}

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