Question
√3cosec 20∘−sec 20∘=
Answer: Option C
:
C
√3cosec20∘−sec20∘=√3sin20∘−1cos20∘
=√3cos20∘−sin20∘sin20∘cos20∘=2[√32cos20∘−12sin20∘]22sin20∘cos20∘
=4cos(20∘+30∘)sin40∘=4cos50∘sin40∘=4sin40∘sin40∘=4.
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:
C
√3cosec20∘−sec20∘=√3sin20∘−1cos20∘
=√3cos20∘−sin20∘sin20∘cos20∘=2[√32cos20∘−12sin20∘]22sin20∘cos20∘
=4cos(20∘+30∘)sin40∘=4cos50∘sin40∘=4sin40∘sin40∘=4.
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