Question
The minimum value of the expression; a+1a;a>0 is:
Answer: Option B
:
B
Soln:
a+1a=(√a−1√a)2+2
For minimum value ofa+1a,we want minimum value of(√a−1√a)2that will be zero.
So, minimum value ofa+1awill be 2. Hence option (b)
2nd method:-By, A.M≥G.Ma+1a2≥√(a×1athusa+1a>2(i.e.,)(a+1a)min will be 2 . option (b).
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:
B
Soln:
a+1a=(√a−1√a)2+2
For minimum value ofa+1a,we want minimum value of(√a−1√a)2that will be zero.
So, minimum value ofa+1awill be 2. Hence option (b)
2nd method:-By, A.M≥G.Ma+1a2≥√(a×1athusa+1a>2(i.e.,)(a+1a)min will be 2 . option (b).
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