Question
A rectangular field is of dimension 15.4m x12.1 m. A circular well of 0.7 m radius and 3 m depth is dug in the field. The mud, dug out from the well, is spread in the field. By how much would the level of the field rise?
Answer: Option B
:
B
Solution: - Volume of earth taken out: πr2h. = π x (0.7)2 x 3 = V.
Area of field without circle: (15.4x12.1)-(π(0.72)) = A (say).
Axh=V
h=2.5 cm
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:
B
Solution: - Volume of earth taken out: πr2h. = π x (0.7)2 x 3 = V.
Area of field without circle: (15.4x12.1)-(π(0.72)) = A (say).
Axh=V
h=2.5 cm
Was this answer helpful ?
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