Question
∫20[x2]dx is (where [.] is greastest integral function
Answer: Option D
:
D
∫20[x2]dx
=∫10[x2]dx+∫√20[x2]dx+∫√3√2[x2]dx+∫2√3[x2]dx
=∫100dx+∫√201dx+∫√3√22dx+∫2√33dx
=√2−1+2√3−2√2+6−3√3
=5−√3−√2
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:
D
∫20[x2]dx
=∫10[x2]dx+∫√20[x2]dx+∫√3√2[x2]dx+∫2√3[x2]dx
=∫100dx+∫√201dx+∫√3√22dx+∫2√33dx
=√2−1+2√3−2√2+6−3√3
=5−√3−√2
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