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Question

1aba1cbc1
=
Options:
A .  1+a2+b2+c2
B .  1−a2+b2+c2
C .  1+a2+b2−c2
D .  1+a2−b2+c2
Answer: Option A
:
A

1aba1cbc1
=1(1+c2)a(a+bc)+b(ac+b)
=1+a2+b2+c2
.

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