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'For all natural numbers N, if P(n) is a statement about n and P(k+1) is true if P(k) is true for an arbitrary natural number k, then P(n) is always true.' State true or false.


Options:
A .   True
B .   False
C .   is true only for a finite number of natural numbers
D .   is true only for all natural numbers greater than 2
Answer: Option B
:
B

For the proof by mathematical induction to work, the statement P(n) must be true for a specific instance of a natural number.
Hence, if P(m) is true, where m is a specific natural number and P(k+1) is true if P(k) is true for an arbitrary natural number k, then, P(n) is true  nm
Without the base case P(m), we cannot say that P(n) is true. Hence, the statement is false.



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