Question
P(n):a2n−b2n is divisible by a+b, ∀ n ϵ N
To prove P(n) using mathematical induction, the base case is
Answer: Option A
:
A
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A
P(n):a2n−b2n is divisible by a+b, ∀ n ϵ N
Since we need to prove P(n) for all natural numbers, the base case will be n=1.
Substituting n=1, we get
a2−b2=(a+b)(a−b) is divisible by a+b
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