Question
(a) Observe the given triangles and explain, why is ΔABC≅ΔFED?
(b) In a ΔABC, ∠B = 50∘ and ∠C is 60∘. Find ∠A.
[4 MARKS]
(b) In a ΔABC, ∠B = 50∘ and ∠C is 60∘. Find ∠A.
[4 MARKS]
Answer:
:
(a) Proof: 2 Marks
(b) Steps: 1 Mark
Final answer: 1 Mark
(a) In ΔABC and ΔFED,
∠B=∠E=90∘ [Given]
∠A=∠F [Given]
BC=ED [Given]
⇒ Two angles and one side of ΔABC are equal totwoangles and one side ofΔFED.
Therefore, ΔABC≅ΔFED [AAS congruence rule]
(b)Sum of the angles of a triangle = 180∘
∠A + ∠B + ∠C = 180∘
∠A = 180∘– (50∘ + 60∘) = 180∘ – 110∘ = 70∘
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:
(a) Proof: 2 Marks
(b) Steps: 1 Mark
Final answer: 1 Mark
(a) In ΔABC and ΔFED,
∠B=∠E=90∘ [Given]
∠A=∠F [Given]
BC=ED [Given]
⇒ Two angles and one side of ΔABC are equal totwoangles and one side ofΔFED.
Therefore, ΔABC≅ΔFED [AAS congruence rule]
(b)Sum of the angles of a triangle = 180∘
∠A + ∠B + ∠C = 180∘
∠A = 180∘– (50∘ + 60∘) = 180∘ – 110∘ = 70∘
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