Question
For the given figures, complete the congruence statements: Â [2 MARKS]
ΔBCA≅ ?               ΔQRS≅ ?
ΔBCA≅ ?               ΔQRS≅ ?
Answer:
:
Each part: 1 Mark
In the given figure,
InΔBCA and ΔBTA,
BC = BT (Given)
CA = TA(Given)
BA = BA(Common side)
Thus, ΔBCA≅ΔBTA [By SSS congruence rule]
In ΔQRS and ΔTPQ,
QT = QS(Given)
PQ = RS(Given)
PT = QR(Given)
Thus, ΔQRS≅ΔTPQ [By SSS congruence rule]
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:
Each part: 1 Mark
In the given figure,
InΔBCA and ΔBTA,
BC = BT (Given)
CA = TA(Given)
BA = BA(Common side)
Thus, ΔBCA≅ΔBTA [By SSS congruence rule]
In ΔQRS and ΔTPQ,
QT = QS(Given)
PQ = RS(Given)
PT = QR(Given)
Thus, ΔQRS≅ΔTPQ [By SSS congruence rule]
Was this answer helpful ?
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