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Question


(a) Find the sum of:
17,(23×52),512
(b) If 57=x28. Find x
(c) Simplify 37÷(2155)
[3 MARKS]


Options:
Answer: Option A
:
Each part: 1 Mark
(a) 17+(23×52)+512
17+(53)512
12+1403584  (LCM of 7, 3, 12 = 84)
11784
(b)  57=x28
 x28=57
  
x=28×(5)7=4×(5)=20
(c)  37÷2155
37×5521
17×557
5549

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