MCQs
Total Questions : 1107
| Page 4 of 111 pages
Question 31.
The
area of a plot is to be determined using Simpson's rule. The following
offsets were taken to a boundary from points along a chain line all
measurements being in metres 12, 15, 22, 29, 36, 38, 31, 22, 17.There
were taken at 100 m intervals.
Consider the following steps in this regard.
1. `(12 + 17)/(2)` = 19.5
2. Sum of the odd ordinates = 22 + 36 + 1 = 89
3. Sum of the even ordinates = 15 + 29 + 38 + 22 = 104
4. 12 + 17 = 39
5. Area = 100 (19.5 + 89 + 104)
6. Area =`(100)/(3)` (39 + 2 x 89 + 4 x 104)
7. Area 100 x 19.5 (104 - 89)
The area of the plot can be determined by using the steps listed above :
Answer: Option D. -> 2, 3, 4 and 6
Answer: Option D. -> ` 30^circ`C
Answer: Option D. -> `4/18 ` m/`sec^2`
Answer: Option D. -> `pm sqrt(10 delta theta)`
Answer: Option C. -> Equal to `Delta` p
Answer: Option B. -> `(16)/(pi d3) (M pmsqrt(m^2 + T^2))`
Answer: Option D. -> `1/pi xx 3/7`
Answer: Option C. -> `(omega h^2)/(2 )` x`(1 + sin varphi)/(1 - varphi)`
Answer: Option C. -> `(4sigma cos alpha)/(Wd)`
Answer: Option A. -> `(pD)/(2sigma_v)`