7th Grade > Mathematics
SIMPLE EQUATIONS MCQs
Total Questions : 118
| Page 3 of 12 pages
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Steps: 1 Mark
Result: 1 Mark
4x+25=7x+10
Now, subtracting 10 on both sides, we get
4x+25−10=7x+10−10
4x+15=7x
Now, subtracting 4x on both sides, we get
4x−4x+15=7x−4x
15=3x
Dividing both sides by 3, we get:
153=3x3
x=5
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Steps: 1 Mark
Result: 1 Mark
2x+13x−2=910
⇒10(2x+1)=9(3x−2)
⇒20x+10=27x−18
⇒10+18=27x−20x
⇒28=7x
⇒7x=28
⇒x=287=4
The value of 'x' is 4.
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Each part: 2 Marks
a) Let the number be y
According to question, (y×6)+4=54
⇒6y=54−4
⇒6y=50
⇒y=506
b) Let the number is y;
According to question, 6+4×y=88.
⇒6+4y=88
⇒4y=88−6
⇒4y=82
⇒y=824
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(a) Correct statement of equation: 1 Markeach
(b) Framing of equation: 1 Mark
Solution: 1 Mark
(a) i) When a number is multiplied with 7 and 4 is added to their product, we get 46 as the final result.
ii) When a number is multiplied with 5,4 is added to their product and their final sum isdivided by 6, the result which we get is 13.
(b) Let Raju's age be x.
Raju's father's age = 3x+5=44
⇒3x+5=44
⇒3x=44−5=39
⇒x=393
⇒x=13years
Raju's age is 13 years.
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Framing of the equation: 1 Mark
Steps: 1 Mark
Answer: 1 Mark
Let the number be ′x′.
Then, the other number is (38−x)
The difference between the numbers is 16.
⇒(38−x)−x=16
⇒38−2x=16
⇒38−16=2x
⇒2x=22
⇒x=11
Other number
=38−x=38−11=27
Question 26. Ethan is given the responsibility of buying a week's supply of food and medication for the dogs and cats at a local shelter. The food and medication for each dog cost twice as much as the supplies for a cat. He needs to feed 164 cats and 24 dogs. His budget is Rs. 4240. How much can Ethan spend on each dog for food and medication? [4 MARKS]
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Framing the equation 2 Marks
Steps: 1 Mark
Result: 1 Mark
Let the expenditure on a cat be y
The expenditure on a dog =2y.
Total expenditure on cats =164×y=164y
Total expenditure of dogs =24×2y=48y
According to question:
164y+24×2y=4240
⇒164y+48y=4240
⇒212y=4240
⇒y=4240212=20
Hence, expenditure of a dog =2y=40
So, for 24 dogs the total expenditure is
=24×40=Rs.960
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Framing the equation: 1 Mark
Steps: 2 Marks
Result: 1 Mark
Let the numerator of a rational number =x
Then the denominator of a rational number =x+3
When numerator is increased by 7, then new numerator =x+7
When denominator is decreased by 1, then new denominator =x+3−1
The new number formed =32
According to the question,
x+7x+3−1=32
⇒x+7x+2=32
⇒2(x+7)=3(x+2)
⇒2x+14=3x+6
⇒3x−2x=14−6
⇒x=8
Numerator = 8, then denominator = 8+3 = 11
Original fraction =811
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Framing the equation: 1 Mark
Steps: 1 Mark
Result: 1 Mark
Let the first number be 9x
Then, second consecutive number =9(x+1)
Third consecutive number =9(x+2),
And, fourth consecutive number =9(x+3)
According to question:
9x+9(x+1)+9(x+2)+9(x+3)=378
⇒9x+9x+9+9x+18+9x+27=378
⇒36x+54=378
⇒36x=378−54
⇒36x=324
⇒x=32436=9
The numbers are 81, 90, 99 and 108.
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Framing the equation: 1 Mark
Steps: 1 Mark
Result: 1 Mark
Let the present age of Gaurav be x.
According to question, In 13 years, Gaurav' age =24
⇒x+13=24
⇒x=11
The expression for Gaurav's age for 20 years from now =x+20
After 20 years, Gaurav's age will be:
x+20
11+20=31years
Since Gaurav's present age is 11 years
∴ After 20 years father's age will be = 6(11)−3=66−3=63
Hence, father's present age = 63−20=43years
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Each part: 1.5 Mark
a) There are many numbers of equations that satisfy y=6
First equation: 4y−8=16
Second equation:7y3−4=10;
b) There arenumberof equations that satisfy y=−8
First equation: 4y−8=−40
Second equation:7y4+24=10