Question
The sum of four consecutive multiples of 9 is 378. Find these multiples? [3 MARKS]
Answer:
:
Framing the equation: 1 Mark
Steps: 1 Mark
Result: 1 Mark
Let the first number be 9x
Then, second consecutive number =9(x+1)
Third consecutive number =9(x+2),
And, fourth consecutive number =9(x+3)
According to question:
9x+9(x+1)+9(x+2)+9(x+3)=378
⇒9x+9x+9+9x+18+9x+27=378
⇒36x+54=378
⇒36x=378−54
⇒36x=324
⇒x=32436=9
The numbers are 81, 90, 99 and 108.
Was this answer helpful ?
:
Framing the equation: 1 Mark
Steps: 1 Mark
Result: 1 Mark
Let the first number be 9x
Then, second consecutive number =9(x+1)
Third consecutive number =9(x+2),
And, fourth consecutive number =9(x+3)
According to question:
9x+9(x+1)+9(x+2)+9(x+3)=378
⇒9x+9x+9+9x+18+9x+27=378
⇒36x+54=378
⇒36x=378−54
⇒36x=324
⇒x=32436=9
The numbers are 81, 90, 99 and 108.
Was this answer helpful ?
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