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12th Grade > Mathematics

SETS MCQs

Sets(11th And 12th Grade)

Total Questions : 60 | Page 6 of 6 pages
Question 51. If a set A has n  elements, then the total number of subsets of A is  
  1.    n
  2.    n2
  3.    2n
  4.    2n
 Discuss Question
Answer: Option C. -> 2n
:
C
Number of subsets of A =nC0 +nC1 + .............+nCn =2n
Question 52. Let A = { x : x ∈ R, |x| < 1};  B = {x : x ∈ R, |x-1| ≥ 1} and 
A ∪ B = R - D, then the set D is
  1.    [x : 1
  2.    [x : 1  ≤ x < 2]
  3.    [x : 1 ≤ x ≤ 2] 
  4.    None of these
 Discuss Question
Answer: Option B. -> [x : 1  ≤ x < 2]
:
B
A = {x:x∈ R, -1 < x < 1}
B = {x:x∈ R:x-1≤ -1 or x-1≥ 1}
= {x : x∈ R:x≤ 0 or x≥ 2}
∴ A∪ B = R - D, where D = {x : x∈ R, 1≤ x < 2}.
Question 53. If n()=700, n(A)=200, n(B)=300 and n(AB)=100, then n(AB)= ___.
  1.    400
  2.    240
  3.    300
  4.    500
 Discuss Question
Answer: Option C. -> 300
:
C
From de-Morgan's law of complementation, we have AB=(AB).
n(AB)=n((AB))
But,n((AB))=n(U)n(AB) by definition of complement of a set.
n(AB)=n(U)n(AB)
=n(U)[n(A)+n(B)n(AB)]
=700(200+300100)
=300
Question 54. In a survey of 200 students from 7 different schools, 50 people do not play NFS, 40 people do not play Dota and 10 people do not play any online game. Find the number of people who do not play both the games.
  1.    80
  2.    70
  3.    60
  4.    50
 Discuss Question
Answer: Option A. -> 80
:
A
Let the numberof people who do not play NFS be n(N') = 50. (Given)
Similarly, the number of people who do not play Dota be n(D') = 40. (Given)
And, thenumberof people who do not play any game be n((N ∪ D)')=n(N'∩ D') = 10. (Given) (de-Morgan's law)
We have to find the numberof people who do not play both the games = n(N∩ D)'.
We know from de-Morgan's law that for sets A and B,
(AB)=AB.
So, n((ND))=n(ND)=n(N)+n(D)n(ND)
=50+4010
=80
Question 55. If A and B are any two sets, then  A(AB)___.
  1.    A
  2.    B
  3.    AC
  4.    BC
 Discuss Question
Answer: Option A. -> A
:
A
If A and B are any two sets, then ABA.
Also, AA(AB)
AA(AB)A
A(AB)=A
Question 56. In a random survey 250 people participated. Out of 250 people who took part in the survey, 40 people have listened to Pink Floyd. 30 people have listened to metallica and 20 people have listened to John Denver. If 10 people have listened to all three then find the no. of people who have listened only Pink Floyd.
  1.    10
  2.    20
  3.    30
  4.    25
 Discuss Question
Answer: Option C. -> 30
:
C
In A Random Survey 250 People Participated. Out Of 250 Peopl...
Let the no. of people who have listened to Pink Floyd be n(P) = 40
Similarly, the no. of people who have listened to Metallica be n(M) = 30
and the no. of people who have listened to John Denver be= n(J) = 20
Also given that the no. of people who listen to all three i.e. n(PMJ)=10
We have to find the no. of people who have listened to only Pink floyd.
Let that no. be x.
Now, from Demorgan's second law, we know that
P(MJ)=(PM)(PJ)
n(P(MJ))=n(PM)+n(PJ)n((PM)(PJ))
n(P(MJ))=30+3030
n(P(MJ))=30
Thus, 30 people listen to only Pink Floyd.
Question 57. If A and B  are two given sets, then A ∩  (AB)cis equal to
  1.    A
  2.    B
  3.    ∅
  4.    A ∩ (Bc).
 Discuss Question
Answer: Option D. -> A ∩ (Bc).
:
D
A∩(AB)c) = A∩ (AcBc)
= (A∩(Ac )∪ (A∩(Bc)
=∅∪ (A∩(Bc) = A∩(Bc).
Question 58. If A={1,2,3,4,5,6}, B={1,2}, then A(AB) is equal to
  1.    A
  2.    N
  3.    A∩B
  4.    A∪B
 Discuss Question
Answer: Option C. -> A∩B
:
C
AB = A - B = {3,4,5,6}
=A(AB) = {1,2}
Question 59. The number of proper subsets of the set {1,2,3} is  ___.
  1.    8
  2.    7
  3.    6
  4.    5
 Discuss Question
Answer: Option B. -> 7
:
B
A set of n elements has 2n subsets.
Every set is a subset of itself.
Thus, the number of proper subsets of a set is 2n1 subsets.
The set {1,2,3} has 3 elements and hence, 231=7 proper subsets.
Question 60. Which of the following is an empty set 
  1.    {x:x is a real number and x2 - 1 = 0}
  2.    {x:x is a real number and x2 +1 = 0}
  3.    {x:x is a real number and x2 - 9 = 0}
  4.    {x:x is a real number and x2 = x + 2}
 Discuss Question
Answer: Option B. -> {x:x is a real number and x2 +1 = 0}
:
B
Sincex2 + 1 = 0, givesx2 = -1
⇒ x =± i
∴ x is not real but x is real (given)
∴ No value of x is possible.

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