7th Grade > Mathematics
RATIONAL NUMBERS MCQs
Total Questions : 120
| Page 3 of 12 pages
Answer: Option B. -> −2357
:
B
−719+−257=(−7×3)(19×3)+−257
=−2157+−257=−2357
:
B
−719+−257=(−7×3)(19×3)+−257
=−2157+−257=−2357
Answer: Option A. -> True
:
A
Any positive number is greater than 0.
:
A
Any positive number is greater than 0.
Answer: Option C. -> 4
:
C
−163÷−43=−163×−34=4
:
C
−163÷−43=−163×−34=4
Answer: Option C. -> 1116
:
C
Let the number to be added be x.
−38+x=516
x=516+38=516+616=1116
:
C
Let the number to be added be x.
−38+x=516
x=516+38=516+616=1116
Answer: Option B. -> False
:
B
A negative number cannot be greater than a positive number.
so,−43<2436
:
B
A negative number cannot be greater than a positive number.
so,−43<2436
Answer: Option C. -> 35
:
C
The space between 0 and 1 is divided into 10 equal parts. The ball lies in sixth place.
Therefore, the location ball lies in is, 610=35
:
C
The space between 0 and 1 is divided into 10 equal parts. The ball lies in sixth place.
Therefore, the location ball lies in is, 610=35
Question 28.
(a) In the figure given below, normally in two jumps frog covers the distance of 9m. One day on seeing the snake frog jumped 15 times more than his normal jump and again he jumped with full strength and covered 12 times more distance than he normally covers in the second jump. Find the distance covered by frog in the second jump and in total.
(b) Are the statements below correct?
(i) The rational numbers −215 and 7−31 are on the opposite sides of 0 on the number line.
(ii) The rational number −3−5 is on the right of −47 on the number line.
[4 MARKS]
(a) In the figure given below, normally in two jumps frog covers the distance of 9m. One day on seeing the snake frog jumped 15 times more than his normal jump and again he jumped with full strength and covered 12 times more distance than he normally covers in the second jump. Find the distance covered by frog in the second jump and in total.
(b) Are the statements below correct?
(i) The rational numbers −215 and 7−31 are on the opposite sides of 0 on the number line.
(ii) The rational number −3−5 is on the right of −47 on the number line.
[4 MARKS]
:
Each part: 2 Marks
(a) In normal jump frog covers 5m in first jump but this time his jump covered =5+(5×15)=6m
In the second jump it covered =4+(4×12)=6m.
So, distance covered in second jump = 6m.
Total distance covered by frog = 6m + 6m = 12m
(b) (i) The statement is false as −215 and 7−31 both are negative numbers and lie to the left side of 0 on the number line i.e. they are at the same side to that of 0 which is left.
(ii) This statement is true as the number −3−5 is actually positive35 and−47 is negative. Therefore, 35 is is on the right of −47 on the number line.
:
There areinfinite rationalnumbersbetween two pointshence we cannot practically calculate the number of rational numbers skipped by the frog.
Question 30. (a) In a number line, there are eight points.They are lying on number line such that US = SR = RT and AP = PQ = QB. Find the rational numbers represented by P, Q, R, S.
(b) Ashley recently opened a store that sells only natural ingredients. She wants to advertise her products by distributing bags of samples in her neighbourhood. It takes one person 2 minutes to prepare one bag.
How many hours will it take to prepare 900 bags of samples if Ashley and 5 of her friends do the work?
[4 MARKS]
(b) Ashley recently opened a store that sells only natural ingredients. She wants to advertise her products by distributing bags of samples in her neighbourhood. It takes one person 2 minutes to prepare one bag.
How many hours will it take to prepare 900 bags of samples if Ashley and 5 of her friends do the work?
[4 MARKS]
:
Each part:2 Marks
(a) As given in the question AP = PQ = QB = 13, because interval of one between AB is divided by into three equal parts.
Similarly, US = SR = RT= 13, since the interval of one between U and T is divided into three equal parts.
So, value of P =2+13=73;
Q =73+13=83
Similarly for R =−1−13=−43;
S =−43−13=−53
(b) Time taken by 1 person to prepare 1 bag = 2 minutes
Time taken by 6 people to prepare 1 bag = 26minutes
Time taken by 6 people (Ashley and her 5 friends) to prepare 900 bags
= 26×900=300minutes=5hrs