7th Grade > Mathematics
RATIONAL NUMBERS MCQs
Total Questions : 120
| Page 2 of 12 pages
Question 11. (a) An investor invested 20 cr in a company for the development of a mobile application. The company distributed this money among various departments to cover up the needs. One-fourth of invested money is allocated to advertisement team. Two third of the remaining money was given to development team. In development team, there are two sub-teams namely Graphics and content team. Among them, it is distributed in such a way that content team will get 32 times more money than that of graphics team. Find the money allocated to each team separately.
(b) Sean is helping his dad build a tiled walkway in their backyard. The walkway will be 60 feet long and 2 feet wide. The local hardware store sells tiles which are 2 by 2 feet and come in boxes of 6.
How many boxes of tiles do they need?
[4 MARKS]
(b) Sean is helping his dad build a tiled walkway in their backyard. The walkway will be 60 feet long and 2 feet wide. The local hardware store sells tiles which are 2 by 2 feet and come in boxes of 6.
How many boxes of tiles do they need?
[4 MARKS]
:
Each part: 2 Marks
(a) Total money invested = 20cr
Amount allocated to advertisement team = 20×14 = 5 cr.
Remaining amount: 20 - 5 = 15cr; Two third of15 cr is allocated for development team =15×23=10cr
Let graphics team got x ,then content team got 32x.
By solving, x +32x =10; x=4
Hence, amount allocated for graphics and content team were 4cr and 6cr respectively.
(b) Area of the walkway = (60 × 2)feet2 =120feet2
Area of 1 tile =(2 × 2)feet2 = 4feet2
Total tiles required = 1204=30
1 box contains 6 tiles.
∴ No. of boxes for 30 tiles
=306=5
:
Each part: 2 Marks
(i) Find the LCM of denominators, i.e. the LCM of 3, 2, 9 and 4 = 36.
Nowmake the denominatorscommon to theabove fraction.
So, 4×123×12 = 4836 ;3×182×18 = 5436 ;7×49×4 = 2836 ;5×94×9 = 4536;
Now arrange the fractions according to their numerator, fraction having large magnitude of numerator will be of greater magnitude.
So, correct sequence is2836,4536,4836,5436.
⇒79<54<43<32
(ii) Find the LCM of denominators, i.e. the LCM of 5, 7, 2 and 20 = 140.
Nowmake the denominatorscommon to theabove fraction.
So, 8×285×28 = 224140;
12×207×20 = 240140;
9×702×70 = 630140;
23×720×7 = 161140;
Now arrange the fractions according to their numerator, fraction having large magnitude of numerator will be of greater magnitude.
So, correct sequence is161140,224140,240140,630140.
⇒2320<85<127<92
:
Formula: 1 Mark
Answer: 1 Mark
The circumference is given by the formula C=2×π×r
So, C=2×π×3=6π
The area is given by the formula A=π×r2
So, A=π×32=9×π
As, π is irrational, so the circumference and area are both irrational.
Answer: Option C. -> −110
:
C
Let the unknown number bex.
−15=310+−25+xx=−15−310+25
Taking LCM, we get,x=−210−310+410x=−110
:
C
Let the unknown number bex.
−15=310+−25+xx=−15−310+25
Taking LCM, we get,x=−210−310+410x=−110
Answer: Option B. -> −2535 and 55−77
:
B
When we have to compare two rational numbers, we first make their denominators equal and then comparetheir numerators.
Consider2440 and 3550. LCM of 40 and 50 is 200.
⟹(24×5)(40×5)=120200
and (35×4)(50×4)=140200≠120200.
Thus,2440 and 3550 are not equivalent.
Considering−2535 and 55−77, LCM of 35 and 77 is 385.
⟹(−25×11)(35×11)=−275385
and (55×5)(−77×5)=−275385.
Thus,−2535 and 55−77 are equivalent rational numbers.
Similarly, on checking the remaining options we find that−2535 and 55−77 is the only pair of equivalent rational numbers.
:
B
When we have to compare two rational numbers, we first make their denominators equal and then comparetheir numerators.
Consider2440 and 3550. LCM of 40 and 50 is 200.
⟹(24×5)(40×5)=120200
and (35×4)(50×4)=140200≠120200.
Thus,2440 and 3550 are not equivalent.
Considering−2535 and 55−77, LCM of 35 and 77 is 385.
⟹(−25×11)(35×11)=−275385
and (55×5)(−77×5)=−275385.
Thus,−2535 and 55−77 are equivalent rational numbers.
Similarly, on checking the remaining options we find that−2535 and 55−77 is the only pair of equivalent rational numbers.
Answer: Option B. -> −2535 and 55−77
:
B
To compare two rational numbers we make their denominators equal and then compare their numerators.
LCM of the denominator 4 and 5 is 20.
2×45×4=820
3×54×5=1520
Comparing820and1520,
we see that820<1520
Hence,25<34.
:
B
To compare two rational numbers we make their denominators equal and then compare their numerators.
LCM of the denominator 4 and 5 is 20.
2×45×4=820
3×54×5=1520
Comparing820and1520,
we see that820<1520
Hence,25<34.
Answer: Option B. -> False
:
B
Any negative number is less than 0. So,−43<0
:
B
Any negative number is less than 0. So,−43<0
Answer: Option B. -> 47
:
B
−1621÷−43=−1621×−34
=47
:
B
−1621÷−43=−1621×−34
=47
Answer: Option C. -> 1314
:
C
1314
is less than 1 as the numerator ofthe fraction is smallerthan the denominator.
While on the other hand, the other fractions are greater than 1 as all the numbers are positive and their numerator is greater than the denominator.
:
C
1314
is less than 1 as the numerator ofthe fraction is smallerthan the denominator.
While on the other hand, the other fractions are greater than 1 as all the numbers are positive and their numerator is greater than the denominator.
Answer: Option B. -> 1628
:
B
Consider the given rational number47.
To make the numerator as 16, we have to multiply it by 4.
Multiplying both numerator and denominatorby 4, we get
4×47×4=1628
Therefore, 1628 is anequivalent rational number of47 with numerator equal to 16.
:
B
Consider the given rational number47.
To make the numerator as 16, we have to multiply it by 4.
Multiplying both numerator and denominatorby 4, we get
4×47×4=1628
Therefore, 1628 is anequivalent rational number of47 with numerator equal to 16.