Ratio And Proportion(Quantitative Aptitude ) Questions and answers for exam Preparation

Quantitative Aptitude

RATIO AND PROPORTION MCQs

Ratio & Proportion, Ratio, Proportion

Total Questions : 895 | Page 53 of 90 pages

Question 521. If Rs. 782 be divided into three parts, proportional to 1/2:2/3:3/4, then the first part is:

Rs. 182
Rs. 190
Rs. 196
Rs. 204

Discuss Question

Answer: Option D. -> Rs. 204

Given ratio = 1/2:2/3:3/4 = 6:8:91st part = 782 * 6/23 = Rs. 204.

Question 522. Two numbers are in the ratio 1:2. If 7 is added to both, their ratio changes to 3:5. The greatest number is:

Discuss Question

Answer: Option C. -> 28

Let the numbers be x and 2x. Then, (x + 7)/(2x + 7) = 3/5x = 14Greatest number = 2 * 14 = 28.

Question 523. Two numbers are in the ratio 3:5. If 9 is subtracted from each, the new numbers are in the ratio 12:23. The smaller number is:

Discuss Question

Answer: Option B. -> 33

Let the numbers be 3x and 5x. Then, (3x - 9)/(5x - 9) = 12/239x = 99 => x = 11The smallest number = 3 * 11 = 33.

Question 524. In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1:2:3. If there are Rs. 30 in all, how many 5 p coins are there?

Discuss Question

Answer: Option C. -> 150

Let the number of 25 p, 10 p and 5 p coins be x, 2x and 3x respectively.Then, sum of their values = [25x/100 + (10 * 2x)/100 + (5 * 3x)/100] = Rs. 60x/10060x/100 = 30 => x = 50.Hence, the number of 5 p coins = 3 * 50 = 150.

Question 525. Seats for Mathematics, Physics and Biology in a school are in the ratio 5:7:8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats?

2:3:4
6:7:8
6:8:9
None of these

Discuss Question

Answer: Option A. -> 2:3:4

Originally, let the number of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively. Number of increased sears are (140% of 5x), (150% of 7x) and (175% of 8x)i.e., (140/100 * 5x), (150/100 * 7x) and (175/100 * 8x)i.e., 7x, 21x/2 and 14xRequired ratio = 7x:21x/2:14x= 14x : 21x : 28x = 2:3:4

Question 526. A and B together have Rs. 1210. If 4/15 of A's amount is equal to 2/5 of B's amount, how much amount does B have?

Rs. 460
Rs. 484
Rs. 550
Rs. 664

Discuss Question

Answer: Option B. -> Rs. 484

4/15 A = 2/5 B => A = (2/5 * 15/4)BA =3/2 B => A/B = 3/2 => A:B = 3:2B's share = 1210 * 2/5 = Rs. 484.

Question 527. Salaries of Ravi and Sumit are in the ratio 2:3. If the salary of each is increased by Rs. 4000, the new ratio becomes 40:57. What is Sumit's present salary?

Rs. 17,000
Rs. 20,000
Rs. 25,500
None of these

Discuss Question

Answer: Option D. -> None of these

Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively. Then, (2x + 4000)/(3x + 4000) = 40/57 6x = 68000 => 3x = 34000Sumit's present salary = (3x + 4000) = 34000 + 4000 = Rs. 38,000.

Question 528. The sum of three numbers is 98. If the ratio of the first to the second is 2:3. And that of the second to the third is 5:8, then the second number is:

Discuss Question

Answer: Option B. -> 30

Let the three parts A, B, C. Then, A:B = 2:3 and B:C = 5:8= (5 * 3/5) : (8 * 3/5) = 3:24/5A:B:C = 2:3:24/5= 10:15:24 => B = 98 * 15/49 = 30.

Question 529. If Rs. 510 be divided among A, B, C in such a way that A gets 2/3 of what B gets and B gets 1/4 of what C gets, then their shares are respectively:

Rs. 120, Rs. 240, Rs. 150
Rs. 60, Rs. 90, Rs. 360
Rs. 150, Rs. 300, Rs. 60
None of these

Discuss Question

Answer: Option B. -> Rs. 60, Rs. 90, Rs. 360

(A = 2/3 B and B = 1/4 C) = A/B = 2/3 and B/C = 1/4A:B = 2:3 and B:C = 1:4 = 3:12A:B:C = 2:3:12A;s share = 510 * 2/17 = Rs. 60B's share = 510 * 3/17 = Rs. 90C's share = 510 * 12/17 = Rs. 360.

Question 530. Ratio of the earnings of A and B is 4:7. If the earnings of A increases by 50% and those of B decreased by 25%, the new ratio of their earnings becomes 8:7. What are A's earnings?

Rs. 21,000
Rs. 26,000
Rs. 28,000
Data inadequate

Discuss Question

Answer: Option D. -> Data inadequate

Let the original earnings of A and B be Rs. 4x and Rs. 7x.New earnings of A = 150% 0f Rs. 4x = (150/100 * 4x) = Rs. 6xNew earnings of B = 75% of Rs. 7x = (75/100 * 7x) = Rs. 21x/46x:21x/4 = 8:7This does not give x. So, the given data is inadequate.