Let ages of Ramu and Shyamu be x and y respectively.x/y = 3/4 => x = 3/4 yAlso (x - 7) / (y - 7) = 2/3=> 3x - 21 = 2y - 143x = 2y + 7But x = 3/4 y3 * 3/4 y = 2y + 79y = 8y + 28 => y = 28 yearsRatio of their ages five years hence= (21 + 5) / (28 + 5) = 26/33.

Let the present ages of Mahesh, Nilesh and Ramesh be m, n and r respectively.
m/n = 5/x   ------ (1)m = r - 18 ------ (2)r + 9 = 47 ------ (3)m - n = r ----- (4)(3) => r = 47 - 9 = 38 years(2) => m = 38 -18 = 20 years(1) => 20/n = 5/x => n = 4x(4) => 4x - 20 = 38=> 4x = 58 => x = 14.5

Let the number of pens that A, B, C and D get be a, b, c and d respectively.a : b = 2 : 1a = c + 25b : c = 2 : 3a : b : c : d = 4 : 2 : 3 : 3a,d get 4p, 3p pens=> 4p - 3p = 25 (given)p = 25=> D gets 3p = 3 * 25 = 75 pens.

Number of men in the colony = 4/7 * 70 = 40.Number of women in the colony = 3/7 * 70 = 40.Number educated women in the colony = 1/5 * 30 = 6.Number of uneducated women in the colony = 4/5 * 50 = 24.Number of educated persons in the colony = 8 /35 * 70 = 16.As 6 females are educated, remaining 10 educated persons must be men.Number of uneducated men in the colony = 40 - 10 = 30.Number of educated men and uneducated men are in the ratio 10 : 30 i.e., 1 : 3.

A:B = 2:3, B:C = 4:5 = (4 * 3/4):(5 * 3/4) = 3:15/4 and C:D = 6:7 = (6 * 15/24):(7 * 15/24) = 15/4:35/8
A:B:C:D = 2:3:15/4:35/8 = 16:24:30:35

Let A = 2x, B = 3x and C = 4x. Then, A/B = 2x/3x = 2/3, B/C = 3x/4x = 3/4 and C/A = 4x/2x = 2/1A/B : B/C : C/A = 2/3 : 3/4 : 2/1 = 8:9:24

Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/dayLet us say 70 men take x days to consume 150 kg.Quantity consumed by each item in x days = (7x/30) kgQuantity consumed by 70 men in x days = (7/30 x)(70) kg= (7/30 x) * (70)  = 960x = 60 days.

Binders                Books             Days        15                          1400                21x                             1600               20x/15 = (1600/1400) * (21/20) => x = 18

Let x = 5k and y = 2k. Then, (8x + 9y)/(8x + 2y) = [(8 * 5k) + (9 * 2k)] / [(8 * 5k) + (2 * 2k)] = 58k/44k = 29/22 (8x + 9y):(8x + 2y) = 29:22

Let A = 2k, B = 3k and C = 5kA's new salary = 115/100 of 2k = 23/10 kB's new salary = 110/100 of 3k = 33/10 kC's new salary = 120/100 of 5k = 6kNew ratio = 23k/10 : 33k/10 : 6k = 23:33:60